Find the length of train Y? Statement I: Train X takes 1 minute to cross a platform of length 1000 meters and 35 seconds to cross a pole. Train Y, moving in the opposite direction to Train X, crosses it in 30 seconds. Statement II: Train Y takes 50 seconds to cross a platform 900 meters long and 40 seconds to cross Train Z, which has a length of 1920 meters and is moving in the opposite direction.

Statement I: Train X crosses a platform of length 1000 meters and a pole in 1 minute and 35 seconds. So train X travel 1000 meters in 25 seconds (60 – 35) Speed of train X = 1000/25 = 40 m/s So length of train X = 40 x 35 = 1400 meters Also, (1400 + length of train Y) = (40 + speed of train Y) x 30 1400 + length of train Y = 1200 + 30 x speed of train Y Length of train Y = 30 x speed of train Y –200………….. (a) This statement alone is not sufficient to answer the question Statement II: Train Y crosses a platform of length 900 meters and train Z having a length of 1920 meters running in the opposite direction in 50 seconds and 40 seconds respectively. Length of train Y + 900 = speed of train Y x 50…………. (1) Also, length of train Y + 1920 = (speed of Y + speed of Z) x 40……….. (2) On solving both equations we got 1020 = 40 x speed of Z –10 x speed of Y 102 = 4 x speed of Z – the speed of Y………….. (3) This statement alone is not sufficient to answer On combining (I + II), Length of train Y = 30 x speed of train Y –200………… (a) Length of train Y + 900 = speed of train Y x 50…………. (1) So, 30 x speed of train Y –200 + 900 = speed of train Y x 50 20 x speed of train Y = 700 Speed of train Y = 700/20 = 35 m/s So length of train Y = 30 x 35 – 200 = 850 meters Both statements together is necessary to answer the question. Hence answer is option C