Question
Find the ratio of average of selling price of each unit
of articles 'B' and 'C' together to cost price of each unit of article 'A' Answer the following questions based on the data provided:  A merchant conducts business with four different articles, labelled as 'A,' 'B,' 'C,' and 'D.' The table below displays the marked price for each article, the percentage of discount offered on each article, and the profit (in Rs.) earned from selling each article, expressed as a percentage of the discount offered on the same article:  Additional information:  => Profit earned on selling article 'A' is Rs. 50 less than that on article 'D'  => 2x – y/2 = 90  => 3y – x/2 = 35 ÂSolution
Given,  2x – y/2 = 90  Or, 4x - y = 180 ....... (I)  And, 3y – x/2 = 35  Or, (6y - x) = 70 ........ (II)  On adding equation (I) with 4 × equation (II), we have;  4x + (-4x) - y + (24y) = 180 + 70 X 4  Or, 23y = 460  So, y = 20  So, 4x = 180 + 20 ..... (From equation I)  Or, x = 200 ÷ 4 = 50  So, marked price of article 'A' = 4 × 50 = Rs. 200  And, percentage discount offered on article 'A' = 1.25y% = 1.25 × 20% = 25%  So, discount offered = 200 × 0.25 = Rs. 50  So, profit earned on article 'A' = 50 × 1.4 = Rs. 70  So, profit earned on article 'D' = 70 + 50 = Rs. 120  Marked price of article 'D' = Rs. 400  Percentage discount offered = 2y% = 2 × 20 = 40%  So, discount offered = 400 × 0.4 = Rs. 160  ATQ;  (120/160) × 100 = {z - (x/2)}  Or, 75 = z - 25  So, z = 100  For article 'A':  Marked price of the article = Rs. 200  Discount offered = Rs. 50  Selling price = 200 - 50 = Rs. 150  Profit earned = Rs. 70  So, cost price = 150 - 70 = Rs. 80 Â
Average selling price of articles 'B' and 'C' together = (240 + 360) ÷ 2 = Rs. 300  Cost price of article 'A' = Rs. 80  So, required ratio = 300:80 = 15:4 Â
Full form of FORTRAN?Â
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