Question
What was the total compound interest on a sum after
three years? Statement I - TheĀ interestĀ afterĀ oneĀ yearĀ wasĀ Rs.Ā 200Ā andĀ theĀ sum was Rs. 1000. Statement II - The difference between simple interest and compound interest on a sum of Rs. 2000 at the end of two years was Rs. 20Solution
From statement I: r = (200 Ć 100)/1000 = 20% P = Rs. 1000 , r = 20%, t = 3 years Hence, from statement I we can find CI. From statement II: SI = (2000 Ć r Ć 2)/100 = 40r CI = 2000 [(1+(r/100)2) ā 1] Therefore,Ā CIĀ āĀ SIĀ = 2000 [(1+(r/100)2) ā 1] ā 40r We can find the value of r from the above equation. Hence , CI can be determined.
2(3/4) of 2880 + 54% of 7520 - ? = 302
Find the value of the following expression:
372 ÷ 56 × 7 – 5 + 2
- What will come in place of (?), in the given expression.
(5³ + 3²) à 2 = ? (1225/25) - (192/96) + (50/5) = ?

What will come in the place of question mark (?) in the given expression?
(555 + 385 - 535) Ć· 15 X ? = 36 X 30
- What will come in place of (?), in the given expression.
75% of 640 ā 20% of 150 = ? `(21 xx 51 + 54)/(9 xx 14 - 30 )` =?
95% of 830 - ? % of 2770 = 650