New Enroll here to Join NaBFID Analyst Into Class on May 6

    Question

    Find the difference between MP of article A and SP of

    article B. I: CP of article A is Rs.224 less than the SP of article B. Discount given on article A is 30% and profit earned on article B is 40% II: SP of article A is Rs.140 more than that of article B . Markup of Rs.264 is given on article A. III: Discount given on article B is Rs.56 more than the profit earned on article A.
    A Only I Correct Answer Incorrect Answer
    B I and II together Correct Answer Incorrect Answer
    C Only II Correct Answer Incorrect Answer
    D Any one Correct Answer Incorrect Answer
    E None together Correct Answer Incorrect Answer

    Solution

    From statement I: CPA + 224 = SPB -------(1 Discount on article A = 30% Profit earned on article B = 40% From statement II: SPA = SPB + 140--------(2 MPA – CPA = 264 ----------(3 From Statement I and II: SPA = 70/100 MPA ------(4 Putting value of SPA in equation 2, 7/10 MPA = SPB + 140------(5 Putting value of CPA from equation 1 in equation 3, we get MPA – SPB = 488 ----(6 Now from equation 5 and 6, we can find the difference between MP of article A and SP of article B.  Hence, we can find the result by combining statements I and II.

    Practice Next

    Relevant for Exams: