Question
Find the difference between MP of article A and SP of
article B. I: CP of article A is Rs.224 less than the SP of article B. Discount given on article A is 30% and profit earned on article B is 40% II: SP of article A is Rs.140 more than that of article B . Markup of Rs.264 is given on article A. III: Discount given on article B is Rs.56 more than the profit earned on article A.Solution
From statement I: CPA + 224 = SPB -------(1 Discount on article A = 30% Profit earned on article B = 40% From statement II: SPA = SPB + 140--------(2 MPA – CPA = 264 ----------(3 From Statement I and II: SPA = 70/100 MPA ------(4 Putting value of SPA in equation 2, 7/10 MPA = SPB + 140------(5 Putting value of CPA from equation 1 in equation 3, we get MPA – SPB = 488 ----(6 Now from equation 5 and 6, we can find the difference between MP of article A and SP of article B. Hence, we can find the result by combining statements I and II.
I: √(100 x4 + 125x4) + 7x + 41/2 = -4x
II: 3√(64y3) x 2y + 19y + 72 = -3y +...
I. 5x² - 28x + 39 = 0
II. 2y² - 13y + 20 = 0
I. 3p² - 14p + 15 = 0
II. 15q² - 34q + 15 = 0
I. 12x2 - 55x + 63 = 0
II. 10y2 - 47y + 55 = 0
I. 7x + 8y = 36
II. 3x + 4y = 14
I. 2x2 – 5x – 63 = 0
II. 2y2 – 7y – 72 = 0
I). 5p2 Â - p - 4 = 0
II). q2 - 12q + 27 = 0
I. 15b2 + 26b + 8 = 0
II. 20a2 + 7a - 6 = 0
I. 8x² + 2x – 3 = 0
II. 6y² + 11y + 4 = 0
l). p² - 26p + 153 = 0
ll). q² - 17q + 72 = 0
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