Question
A person invests ₹80,000 in a mutual fund. The
investment grows at a rate of 8% per annum, compounded annually. After 3 years, he decides to withdraw ₹10,000 and reinvest the remaining amount at the same rate. After another 2 years, the remaining amount grows at the same rate, and he sells the entire amount. What is the total amount he receives after 5 years?Solution
Initial investment = ₹80,000. Rate = 8% per annum, compounded annually. Amount after 3 years: A = P(1 + r/n)^(nt) = ₹80,000(1 + 0.08)^3 = ₹80,000 × 1.2597 = ₹1,00,776. Amount remaining after withdrawing ₹10,000 = ₹1,00,776 - ₹10,000 = ₹90,776. Amount after 2 more years: A = P(1 + r/n)^(nt) = ₹90,776(1 + 0.08)^2 = ₹90,776 × 1.1664 = ₹1,06,930. Total amount = ₹1,06,930. Final amount received = ₹1,06,930. Closest option: b) ₹1,06,930.
625, 125, 50, 30, 24, ?
- What will come in place of (?) in the given number series.
2, 6, 15, 31, 56, ? 50, 49.5, ?, 45.5, 42, 37.5
12, 25, 51, ?, 207, 415
- 45, 71.01, 98.05, 126.14, ?
62, 87, 137, ?, 312, 437
114, 146, 210, 306, 434, ?
8, 9, 125, ?, 1331, 169
8 12 30 105 ? 2598.75
...- 741, 852, 1074, 1407, ?