Question
A invest Rs. X at 10% compound interest for 3 years. If
difference between the interest of 3rd year and 2nd year is Rs. 1210, find the value of X.Solution
Let the sum invested be 1000k. Amount after 1 year = 1000k × 1.1 = 1100k Sum after 2 years = 1100k × 1.1 = 1210k Interest of 2nd year = 1210k – 1100k = 110k Sum after 3 years = 1210k × 1.1 = 1331k Interest of 3rd year = 1331k – 1210k = 121k => 121k – 110k = 1210 ⇒ 11k = 1210 ⇒ k = 110 Hence, X = 1000 × 110 = Rs. 110000
What will come in place of the question mark (?) in the following series?
?, 65, 37, 73, 29, 81
What will come in place of the question mark (?) in the following series?
77, 198, 342, 511, 707, ?
15, 23, 30, 36, 41, ?
What will come in place of the question mark (?) in the following series?
1458, ?, 162, 54, 18, 6
14, 17, 23, 32, ?, 59
60, 100, 160, 240, ?, 460
69, 35.5, 39.5, 68.25, 152.5, ?
66, 17, 81, ?, 100, -21
1, 7, 37, 187, 937, ?
612, 487,?, 396, 388, 387
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