Question
In a circle of radius 17 cm, a chord is at a distance 8
cm from the centre. The length of the chord is:Solution
Perpendicular from centre to chord bisects the chord. Let half of the chord = x Then, x^2 + 8^2 = 17^2 x^2 + 64 = 289 x^2 = 225 x = 15 So chord length = 2x = 30 cm
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