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Let students who play only Football be 20x. So, students who play only Badminton = 10x And, students who play only Cricket = 25x Now, students who play all 3 games together = 5x Now, students who play Cricket and Football but not Badminton = 7.5x And, students who play Football and Badminton together = 15x Now, students who play Football and Badminton but not Cricket = 10x Now, students who play both Cricket and Badminton together = 10x So, students who play Cricket and Badminton but not Football = 5x According to question, => 25x + 7.5x + 20x + 5x + 5x + 10x + 10x = 990 => x = 12 
Total number of students who play Cricket = 300 + 90 + 60 + 60 = 510 Total number of students who play Badminton = 60 + 60 + 120 + 120 = 360 Required % = [(510 – 360)/360] × 100 = 41(2/3)%
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