The number of employees in department P is approximately what percentage of the total number of employees in all the departments together?

Solution

Let the number of employees in department T be ‘x’. Number of employees in department M = 2x Number of employees in department N = 50 + x Number of male employees in department M = 150 According to the question, => 150 = 62.5% of 2x => 2x = 240 => x = 120 So, Number of employees in department T = 120 Number of employees in department M = 2x = 240 And Number of employees in department N = 50 + x = 170 Total number of employees in all the departments = 5 × 168 = 840 Remaining employees = 840 – (120 + 170 + 240) = 310 Now, the difference between the number of employees in department P and department Q is 10 and department P has the third highest number of employees. Let number of employees in department Q = y => P = y + 10 According to the question, => (y + 10) + y = 310 => 2y = 300 => y = 150 Number of employees in department Q = 150 Number of employees in department P = y + 10 = 160 Required % = (160/840) × 100 = 19% approx.