Question

Study the following information carefully and answer the questions given below: A company has five departments namely P, Q, M, N and T. The number of employees in all the departments are different and department P has the third highest number of employees. The number of employees in department M is twice the number of employees in department T. The number of employees in department N is 50 more than the number of employees in department T. The average number of employees in all the departments is 168. The number of male employees in department M is 150 which is 62.5% of the number of employees in department M. The difference between the number of employees in department P and department Q is 10.

The number of employees in department P is approximately what percentage of the total number of employees in all the departments together?

A 11% Correct Answer Incorrect Answer
B 23% Correct Answer Incorrect Answer
C 35% Correct Answer Incorrect Answer
D 19% Correct Answer Incorrect Answer
E None of these Correct Answer Incorrect Answer

Solution

Let the number of employees in department T be ‘x’. Number of employees in department M = 2x Number of employees in department N = 50 + x Number of male employees in department M = 150 According to the question, => 150 = 62.5% of 2x => 2x = 240 => x = 120 So, Number of employees in department T = 120 Number of employees in department M = 2x = 240 And Number of employees in department N = 50 + x = 170 Total number of employees in all the departments = 5 × 168 = 840 Remaining employees = 840 – (120 + 170 + 240) = 310 Now, the difference between the number of employees in department P and department Q is 10 and department P has the third highest number of employees. Let number of employees in department Q = y => P = y + 10 According to the question, => (y + 10) + y = 310 => 2y = 300 => y = 150 Number of employees in department Q = 150 Number of employees in department P = y + 10 = 160 Required % = (160/840) × 100 = 19% approx.

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