Question
A boat moves at 40 km/hr downstream and 10 km/hr
upstream. How long will it take to cover 150 km in still water?Solution
ATQ,
Let the boat’s speed in still water be x km/hr, and current speed be y km/hr. Then: Downstream speed = x + y = 40 ......(1) Upstream speed = x - y = 10 ......(2) Adding (1) and (2): x + y + x - y = 40 + 10 → 2x = 50 → x = 25 km/hr Time to travel 150 km in still water = 150 / 25 = 6 hours
Find the value of the given expression.
4 × (tan 45° – cos 60°)
- Find the maximum value of (10sin A + 24cos A).
If cos θ + sin θ = m, sec θ + cosec θ = n then n(m 2 – 1) is equal to?
cot 13Ëš Â
 cot 14˚  ...Find the value of tan(75°) using the identity for tan(A+B).
What is the value of cosec30° sec30°?
If 8sin²x + 4cos²x − 6 = 0, then find the value of sinx, given that 0° < x < 90°.
If √3 tan 2θ – 3 = 0, then find the value of tanθ secθ – cosθ where 0 < θ < 90°
- If secx – tanx = 1/√3, then the value of secx × tanx is:
ABC is an isosceles triangle where AB = AC which is circumscribed about a circle. If P is the point where the circle touches the side BC, then which of ...
Relevant for Exams:
