Question
A boat moves downstream at 45 km/h, which is (25/10) m/s
faster than its upstream speed. If it covers (D + 24) km downstream and (D - 36) km upstream in a total of 8.5 hours, find the approximate value of ‘D’.Solution
ATQ, Upstream speed = 45 - (25/10) × (18/5) = 45 - 9 = 36 km/h Multiply throughout by LCM of 45 and 36 → LCM = 180 Or, 4 × (D + 24) + 5 × (D - 36) = 8.5 × 180 Or, 4D + 96 + 5D - 180 = 1530 Or, 9D - 84 = 1530 Or, 9D = 1614 Or, D = 179.33 Approximate value: D ≈ 179
If sec A + tan A = 3 then the value of cot A is:
If sin(x-y) = 1 and cos(x+y) = 1 /√2 then what is measure of angle x.
If tan A = 1 and tan B = √ 3, what is the value of cos A . cos B - sin A . sin B?
If sec(2A + B) = 2 and cos(A + B) = (1/√2) , find the value of {sec 2B + tan (A + B) } given that 0o < A, B < 90o
A man is standing at a point 40 meters away from a tower. The angle of elevation of the top of the tower from the point is 45°. After walking 20 meters...
If tan θ = (2/√5), then determine the value of cos2 θ
From a point "A" on the ground, the angle of elevation to the top of a tower measuring 12 meters in height is 30°. Determine the horizontal distance be...
- If cosec [180° − (3q/2) ] = √2, 0° < q < 90°, then find the value of {(2/√3) X cos q - 4 cos 3q}.
Two buildings are 40 meters apart. The height of one building is 20 meters. From the top of the shorter building, the angle of elevation of the top of t...
If α means +, β means -, ɣ means x, θ means ÷ then 30 θ 10ɣ 5α 10β20 is