Question
A kayaker covers 64 km upstream and 96 km downstream in
8 hours and 6 hours, respectively. Find the time taken by the same kayaker to cover 140 km in still water.Solution
ATQ, Let speed of the kayaker in still water be βxβ km/h and speed of the stream be βyβ km/h Upstream speed of kayaker = (x β y) = (64/8) = 8 km/h --------- (I) Downstream speed of kayaker = (x + y) = (96/6) = 16 km/h ---------- (II) On adding equation (I) and equation (II), we have: 2x = 24 Or, x = 12 So, speed of the kayaker in still water = 12 km/h Therefore, time taken by the kayaker to cover 140 km in still water = (140/12) = 11.67 hours
(3x Γ 9(x+1)) / 27(2xβ1) = 1, then find 'x'.
Β + 189500 β 22650 + 48Γ ? β 352Γ18 = 162674
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If (528 β 507 + 195) Γ· 11 + β1296 = x, then {(x/2) + 10} = ?
In β ABC, MN β BC, the area of quadrilateral MBCN=130 sqcm. If AN : NC = 4 : 5, then the area of β MAN is:
If (a2 + 1/a2) = 11, then find the value of (a3 - 1/a3).
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The value of:
Β οΏ½...Find βxβ if (xΒ³+3x)/(3xΒ²+1) = 189/61
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