Question
A man can row one quarters of a kilometer against the
stream in 30/4 minutes and return in 5/2 minutes. The speed of the man in still water is:Solution
Distance covered upstream in 30/4 minutes = 1/4 Km Distance covered upstream in 1 hour = 1/4× 4/30× 60 = 2 km/hr Distance covered downstream in 5/2 minutes = 1/4 km Distance covered downstream in 1 hour = 1/4 × 2/5× 60 = 6 km/hr Speed of the man in still water = 1/2(2 + 6) = 4 km/hr
More Boats and streams Questions
12 % of 72 × 25 – (x ÷ 20) × (16 ÷ 24) × 36 + 1/5 × x = (4 ÷ 12) × 36 ÷ 1/4
√( (664+ √(136+ √(59+ √(21+ √(7+ √81) ) ) ) ) ) = ?
3? x 23 ÷ √ 256 = 40.5
3% of 3000 × ?% of 2000 = 3600
What will come in the place of question mark (?) in the given expression?
? = (40% of 80% of 6400) ÷ 64
53 – 8 = ? + 126
- Simplify the following expression:
(48% of 800 × 3) ÷ 6 + 440 ÷ √25 - 14² (√ 121 x 41) + (3√343 x √289 ) = ? x 19  Â
25% of (?) + (1/4)of 5600 = 2500 – 20% of 1940Â
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