Question
A boat can cover 66 km upstream and 165 km downstream in
13 hours. Speed of the stream is how much less than the speed of the boat in still water if the boat can cover 55 km upstream and 110 km downstream in 9 hours?Solution
ATQ, Let the upstream speed and downstream speed of the boat be x km/h and y km/h, respectively. So according to question: 66/x + 165/y = 13 ………………. (i) Also, 55/x + 110/y = 9 ……….. (ii) Solving (i) and (ii), we get x = 11 and y = 22 So, the upstream speed and downstream speed of the boat are 11 km/h and 22 km/h, respectively. Speed of the boat in still water = (11 + 22)/2 = 16.5 km/h Speed of the stream = (22 – 11)/2 = 5.5 km/h So, the desired difference = 16.5 – 5.5 = 11 km/h
If p = 24 - q - r and pq + r(q + p) = 132, then find the value of (p² + q² + r²).
((99.9 - 20.9)² + (99.9 + 20.9)² )/(99.9 x 99.9 + 20.9 x 20.9) = ?
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Find the value of the given expression-
(4x+4 -5× 4x+2) / 15×4x – 22×4x
If 4x² + y² = 40 and x y = 6, then find the value
of 2x + y?
If p = 40 - q - r and pq + r(q + p) = 432, then find the value of (p² + q² + r²).
47.98 × 4.16 + √325 × 12.91 + ? = 79.93 × 5.91
If x + y = 4 and (1/x) + (1/y) = 24/7, then the value of (x3 + y3).
- If p = 20 - q - r and pq + r(p + q) = 154, then find the value of (p² + q² + r²).
If a = (√2 - 1)1/3, then the value of (a-1/a)3 +3(a-1/a) is:
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