Question
The speed of the stream is 10 km/h. Boat ‘A’ covers
180 km distance against the stream in 6 hours and boat ‘B’ covers 90 km distance against the stream in 2 hours. The speed of boat ‘A in still water is how much percent of the speed of boat ‘B’ in still water?Solution
Speed of boat ‘A’ upstream = 180/6 = 30 km/h Speed of boat ‘B’ upstream = 90/2 = 45 km/h Speed of the boat ‘A’ in still water = 30 + 10 = 40 km/h Speed of the boat ‘B’ in still water = 45 + 10 = 55 km/h Required percentage = (40/55) × 100 = 72.7%
How is LETTER written in the code language?
I. MASTER is written as NZHGVI
II. BOTTLE is written as YLGGOV
Statements: G ≤ H, H ≤ J, L < G
Conclusions: I. L < H II. J > L
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