Question
A ship covers a distance of 240 km downstream in a time
that is 2 hours shorter than the time it takes to cover the same distance upstream. The ship's upstream speed is 60% of its downstream speed. The task is to calculate the speed of the ship in still water under these conditions.Solution
ATQ; Let the downstream speed of the ship be ‘a’ km/h and upstream speed of the ship be ‘0.6a’ km/h then, (240/a) + 2 = (240/0.6a) Or, (400/a) – (240/a) = 2 Or, 160 = 2a So, a = 80 So, upstream speed of the ship = 0.6a = 48 km/hr Downstream speed of the ship = a = 80 km/hr Since, speed of ship in still water = {(downstream speed + upstream speed)/2} So, speed of the ship in still water = (80 + 48)/2} = 64 km/hr
Statements: M % C & G @ T $ D; W % M # PÂ
Conclusions :Â Â Â Â Â I. D % CÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â II. M % GÂ Â Â Â Â Â Â Â Â Â Â Â Â ...
Statements: G > N > P = E ≥ H < L; M < E < B < C = Q > X; U > W > Y = Q > H
Conclusions:
I). U > P
II). Y > P
...Statements: A > B; C > D; E ≥ A; F = C; C < B
Conclusions:
(i) B > D (ii) A > F (iii) F < E
...Which of the following symbols should replace the question mark in the given statement in order to make conclusion 'B>Z' as well as 'C>X' definitely tr...
Statements: F % W, W © R, R @ M, M $ D
Conclusions:
 I.D @ R                               II.M $ F�...
Statements: H > S ≥ F = B ≤ U≤ T; E ≤ B ≤ K
Conclusions:I. K > F II. K = F
Statements:  B > K < Y, E > C ≥ O = Y
Conclusions:
I. C > B
II. E ≤ Y
III. E > K
IV. O ≥ K
...Statements: B > D = C ≥ E ≥ G, C = H ≤ I < F
Conclusions:
I. B > H
II. I ≥ G
III. F > DStatement: E < F ≤ G = H, I ≥ G ≤ J ≤ K
Conclusion: I. K > EÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â II. H > K
...Statement: W>Y<X<Z=U>S; W<T ≥V
I. Y<T
II. X > V
