Question
A ship requires 9 hours to travel a distance of 216 km
downstream and 210 km upstream. If the ratio of the ship's speed in calm waters to the speed of the current is 8:1, determine the time it takes for the ship to traverse 336 km in calm waters.Solution
ATQ, Let, speed of Ship in still water and speed of stream be '8a' km/h and 'a' km/h respectively. So, (216/9a) + (210/7a) = 9 (24/a) + (30/a) = 9 a = 6 Speed of Ship in still water = 8a = 48 km/h Required time = (336/48) = 7 hrs
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
? * 4.89 = (410.15 ÷ 13.97) % of 6190 - 1342.77
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(9/10 of 3999.79) - √2499.83 + (17.81% of 1199.81) = ?
(1963.33 ÷ 6.5 - 193.99)/? = 753.02 ÷ 26.98
960.11 ÷ 23.98 × 5.14 – 177.9 = √?Â
What will be the approximate value of the following questions.
(√143.74 + 29.89% of 720.27) × (5/9 of 539.79) = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
If 4tan4 + 9 – 12tan2 = 0, then find the value of cot.
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