Question
A boat covers a distance of 150 km while moving in a
downstream in 5 hours. When the boat covers a distance of 60 km in still water in 3 hours, then What will be the distance covered by boat (in km) in upstream in 8 hours.Solution
Let the speed of the boat in still water and speed of the stream will be taken as 'x' km/hr & 'y' km/hr respectively. ATQ,we can say that Speed of the boat in downstream = (x + y) = (150/5) = 30km/hr ....(I) Also, 'x' = (60/3) = 20.....(II) So, from equation (II), we can say that 20 + y = 30 Or, y = 10 So, distance covered in upstream will be = (x - y) x 8 = (20 - 10) x 8 = 80km
?% of (168 ÷ 8 × 20) = 126
20% of 1500 – 75% of 200 = 125% of ?
Find the value of 16 X [(8 - 5) of 12 ÷ 4].
√196 + (0.25 × 144) + 19 = ? + 72
22 * 6 + 45% of 90 + 65% of 180 = ?
52% of 400 + √(?) = 60% of 600 - 25% of 400
(25 × 12 + 30 × 8 – 22 × 10) = ?
What will come in the place of question mark (?) in the given expression?
(240% of 175 ÷ √16) X 6 + 80% of 400 = ?3 + 179 + 42
What will come in the place of question mark (?) in the given expression?
(144 × 16 ÷ 12) × 6 = ?
808 ÷ (128)1/7 + 482 = 4 × ? + 846
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