Question
The ratio of the speed of boat βAβ in still water,
the speed of boat βBβ in still water and the speed of the current is 7:5:2, respectively. If the time taken by boat βAβ to travel (6D β 30) km downstream is equal to the time taken by boat βBβ to travel (D + 60) km upstream, then find the value of βDβ.Solution
Let, the speeds of boat βAβ and boat βBβ, in still water and the speed of the current be 7x km/hr, 5x km/hr and 2x km/hr, respectively. According to the question, (6D β 30)/(7x + 2x) = (D + 60)/(5x β 2x) Or, 18D β 90 = 9D + 540 Or, 9D = 630 Or, D = 70
Witness to character may be
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