Question
The speed of the stream is 20 km/h. Boat ‘A’ covers
120 km distance against the stream in 6 hours and boat ‘B’ covers 120 km distance against the stream in 5 hours. The speed of boat ‘B’ in still water is how much percent of the speed of boat ‘A’ in still water?Solution
Speed of boat ‘A’ upstream = 120/6 = 20 km/h Speed of boat ‘B’ upstream = 120/5 = 24 km/h Speed of the boat ‘A’ in still water = 20 + 20 = 40 km/h Speed of the boat ‘B’ in still water = 24 + 20 = 44 km/h Required percentage = (44/40) × 100 = 110%
The smallest side of a right-angled triangle is 7 cm less than the side of a square of perimeter 76 cm. The second largest side of the right-angled tria...
A right-angled triangle has one leg of 12 cm and the hypotenuse of 13 cm. Find the length of the other leg.
- Determine the area of a triangle if its base measures 19.2 cm and its corresponding height is 24.5 cm.
- The sides of two similar triangles are in the ratio 5:7. The areas of these triangles are in the ratio:
∠A, ∠B, and∠C are three angles of ∆ABC.if ∠A-∠B=15°, ∠B-∠C =30°,then ∠A, ∠B and ∠C are?
If each side of an equilateral triangle is 12 cm, then its altitude is equal to:
- Determine the perpendicular drawn from a vertex to the opposite side in an equilateral triangle with side length 8√3 cm.
What is the height of an equilateral triangle if each side measures 8√3 cm?
- In triangle DEF, GH is drawn parallel to side EF. If DG = 9 cm, GE = 3 cm and DH = 6 cm, find DF.
The area of an equilateral triangle is 64√3 cm2. Find the radius of the circle that circumscribes the triangle.
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