Question
The speed of the stream is 20 km/h. Boat βAβ covers
120 km distance against the stream in 6 hours and boat βBβ covers 120 km distance against the stream in 5 hours. The speed of boat βBβ in still water is how much percent of the speed of boat βAβ in still water?Solution
Speed of boat βAβ upstream = 120/6 = 20 km/h Speed of boat βBβ upstream = 120/5 = 24 km/h Speed of the boat βAβ in still water = 20 + 20 = 40 km/h Speed of the boat βBβ in still water = 24 + 20 = 44 km/h Required percentage = (44/40) Γ 100 = 110%
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