Question
The speed of the stream is 12 km/h. Boat ‘A’ covers
100 km distance against the stream in 5 hours and boat ‘B’ covers 80 km distance against the stream in 2 hours. The speed of boat ‘B’ in still water is how much percent of the speed of boat ‘A’ in still water?Solution
Speed of boat ‘A’ upstream = 100/5 = 20 km/h Speed of boat ‘B’ upstream = 80/2 = 40 km/h Speed of the boat ‘A’ in still water = 20 + 12 = 32 km/h Speed of the boat ‘B’ in still water = 40 + 12 = 52 km/h Required percentage = (52/32) × 100 = 162.5%
A $ B means A X B, A & B means A - B, A % B means A ÷ B and A # B means A + B, then what is the value of 320 & 80 # 120 % 24 $ 50?
Statements:
V ≤ P < S = B; T < U ≤ I = B; N < J < T
Conclusions:
I. J > P
II. N < S
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