Question
A boy can swim a certain distance downstream in 3 hours
and return in 7 hours. If the rate of stream is 4 kmph then what is the speed of boy in still water?Solution
Let the speed of the boy in still water be x kmph. Then, (x + 4) × 3 = (x – 4) × 7 => 3x + 12 = 7x - 28 => 4x = 40 => x = 10 kmph
(115.25 + 324.78) ÷ 4.99 = ?2 – 56.44Â
`[(sqrt(750) xx15.981) -: 54.003]` `xx` ? = 6997.81001
25.19% of (?2 ÷ 38.87 × 4679.94) = 6299.82 ÷ 419.78 × 50.15
?2 - 12.5% of 647.99 = 24.98% × 363.97 + 5% of 1059.98Â
What will come in the place of question mark (?) in the given expression?
?2 = {40% of (552 – 352 )} – 44
Amit and Bheem can individually finish a task in 10 days and 15 days, respectively. If they work together to complete the task an...
(752.09 - 43.04 x 7.94) ÷  16.9 = ?
25.902 × 78.095 + 999.996% of 200.08 + 20.005 % of 7999.997 = ? × 15.008 × 33.009
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)