New Enroll in RBI Grade B New Batch - Starts on May 21

    Question

    A cylindrical conductor of length L and radius R has its

    radius increasing linearly from R at one end to 2R at the other. A constant current I flows through it. If the resistivity of the material is ρ, find the total resistance of the conductor.
    A (ρL)/(3πR²) Correct Answer Incorrect Answer
    B (2ρL)/(3πR²) Correct Answer Incorrect Answer
    C (3ρL)/(2πR²) Correct Answer Incorrect Answer
    D (ρL)/(2πR²) Correct Answer Incorrect Answer

    Solution

    To find the total resistance of the conductor, we need to consider a small element of the cylindrical conductor of thickness dx at a distance x from the end with radius R. Let the radius of the conductor at a distance x from the end with radius R be r(x). Since the radius increases linearly from R to 2R over a length L, the rate of increase of the radius with respect to the length is (2R-R)/L = R/L. So, the radius at a distance x is given by: r(x) = R + (R/L)x = R(1+x/L) The cross-sectional area of this small element at distance x is:

    Practice Next

    Relevant for Exams: