Question
The speed of a boat in still water is 11 times the speed
of the stream. If the difference between the upstream and downstream speed of the boats is 20 km/hr, then find the time taken by the boat to travel 200 km in upstream.Solution
Let the speed of the stream be ‘x’ km/hr Therefore, speed of the boat in still water = 11x km/hr Upstream speed of the boat = 11x – x = 10x km/hr Downstream speed of the boat = x + 11x = 12x km/hr According to the question, 12x – 10x = 20 => 2x = 20 => x = 10 Therefore, upstream speed of the boat = 10x = 100 km/hr Required time taken = 200/100 = 2 hours
30% of 215 + 135% of ? = 469.5
95% of 830 - ? % of 2770 = 650
Solve the following equation.
143 + 14.3 + 1.43 + 0.143 + 0.0143 =?
81% of 2300 – 34% of 550 = ?
135.37 – 50.24 + 629.09 – 199.50 = ? – 214.68 + 42.65
- Simplify the expression:
30% of [140% of (50 + 30) + 110] ÷ 70 × 100 - What will come in place of (?), in the given expression.
(56 × 3) + (480 ÷ 6) = ? 11 × 25 + 12 × 15 + 14 × 20 + 15 = ?
What will come in place of the question mark (?) in the following expression?
18 × 16 – 11 × 4 = 15² + ?
{(3/8) + (5/6)} × 120 – 53 = ?Â
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