Question
Sumit can swim 12 km upstream and 16 km downstream in 5
hours. If ratio of speed of stream to that of speed of Sumit in upstream is 1:2, then find the speed of Sumit in still water.Solution
Let speed of stream be x km/hr. And upstream speed of Sumit is 2x km/hr. Downstream speed = 2x + x + x = 4x km/hr => 12/2x + 16/4x = 5 ----- (i) => x = 2 Speed of Sumit in still water = (4x + 2x)/2 = 6x/2 = 12/2 = 6 km/hr
6000 3002 1503 ? 378.75 191.375 97.6875
...1, 27, ?, 343, 729, 1331
(32.03 + 111.98) ÷ 18.211 = 89.9 – 20.23% of ?
51 53 109 332 ? 6686
...9 4.5 4.5 9 36 ?
5 16 ? 66 119 200
...1 1 8 4 27 9 ?
...What will be the next number in the series?
2, 7, 23, 70, ?
There are three series given below which are following with the same pattern.
Series I: 1, 12, 38, 193, 1355
Series II: 6, B, C, D, E
...Direction: Which of the following will replace ‘?’ in the given question?
5, 18, ‘?’, 126, 296, 586, 1044
Relevant for Exams:
