Question
Sumit can swim 12 km upstream and 16 km downstream in 5
hours. If ratio of speed of stream to that of speed of Sumit in upstream is 1:2, then find the speed of Sumit in still water.Solution
Let speed of stream be x km/hr. And upstream speed of Sumit is 2x km/hr. Downstream speed = 2x + x + x = 4x km/hr => 12/2x + 16/4x = 5 ----- (i) => x = 2 Speed of Sumit in still water = (4x + 2x)/2 = 6x/2 = 12/2 = 6 km/hr
A $ B means A X B, A & B means A - B, A % B means A ÷ B and A # B means A + B, then what is the value of 320 & 80 # 120 % 24 $ 50?
Statements:
V ≤ P < S = B; T < U ≤ I = B; N < J < T
Conclusions:
I. J > P
II. N < S
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