Question
In a fixed time, a boy swims thrice the distance along
the current that he swims against the current. If the speed of the current is 5 km/hr, the speed of the boy in still water isSolution
Let the rate of swimming in still water be x km/hr Rate down-stream = (x + 5) km/hr Rate up-stream = (x – 5) km/hr According to the question, (x + 5) t = 3 (x – 5) × t x + 5 = 3x – 15 x = 10 km/hr
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