Question
Three numbers a, b and c are such that a = 120, (a + b)
= 420 and (c β b) = 90. Find their average.Solution
ATQ, Given, a = 120, (a + b) = 420 and (c β b) = 90 Therefore, b = 420 β 120 = 300 And, c = 300 + 90 = 390 Required average = (120 + 300 + 390)/3 = 270
? = 6.25% of 240 + 25 2 + 17 2 β 16 Γ 17
1024 Γ· 16 + 800 Γ· β64 + ? = 200 * 2
[1.45 X 1.45 X 1.45 + 0.55 X 0.55 X 0.55 + 4.785] = ?
20 + 160/? Γ 20 = 420
(5832) 2/3 / (104976)3/4 X ? = ( `sqrt(18)` ` ` ) 5
...β? + β1296 + β729 = 464/4Β Β
3(2/3) of 2(5/11) of 5(2/5) of 75 = ?
- Simplify:

560 ÷ 14 × 3 – 25 = ?