Question
Three numbers a, b and c are such that a = 120, (a + b)
= 420 and (c – b) = 90. Find their average.Solution
ATQ, Given, a = 120, (a + b) = 420 and (c – b) = 90 Therefore, b = 420 – 120 = 300 And, c = 300 + 90 = 390 Required average = (120 + 300 + 390)/3 = 270
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