Question
In a cricket match, the average score of 11 batsmen was
42 runs. When 2 batsmen got out, the average score of the remaining batsmen dropped to 38 runs. Determine the average score of the two batsmen who got out.Solution
Total score of 11 batsmen = 11 X 42 = 462 runs Total score after 2 batsmen got out = 9 X 38 = 342 runs So, total score of the 2 batsmen who got out = 462 - 342 = 120 runs So, required average = 120 ÷ 2 = 60 runs
More Average Questions
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30% of [140% of (50 + 30) + 110] ÷ 70 × 100 24% of 15% of 500 + 122 = ?2 – (232 ÷ 2)
If (3 × 144 – 252 ÷ 14) ÷ 18 = √1024 – x, then find the value of ‘x’.
- What will come in place of (?), in the given expression.
144 ÷ √36 + 13² – 100 = ? {(80% of 650 + 25 × 12) – 20 × ?} = 760
31% of 1900 - ? = 73
Simplify the following expression.
(3-3 × 3 + 3 ÷ 3 + 3 × 5) × 2 of 5 + (2 + 2 ÷ 2 + 2 × 2 - 2)
Find the value of ‘x’ if (5 × 196 – 340 ÷ 17) ÷ 20 = √1600 – x.
The value of 42 ÷ 9 of 6 - [64 ÷  48 x 3 – 15 ÷ 8 x (11 – 17) ÷ 9] ÷ 14 is:
√529 + √64 + 92 = ?
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