Question
In an office of 35 employees, the average salary is
₹48,000. One employee earning ₹45,000 resigns, and 4 new employees with an average salary of ₹50,000 join. When the manager’s salary is also included, the average salary becomes ₹49,000. What is the salary of the manager?Solution
Initial total salary = 35 × 48000 = ₹16,80,000
The sum of salaries of 4 new employees = 4 × 50000 = ₹2,00,000 Let the salary of the manager be ‘y’ rupees.
New total salary without manager = 1680000 - 45000 + 200000 + y = (18,35,000 + y)
New total number of people = 35 - 1 + 4 + 1 = 39
New total salary = 39 × 49000 = ₹19,11,000
So, manager’s salary = 1911000 - 1835000 = ₹76,000
12.5% of (100 + ?) = 40
2/9 of 5/8 of 3/25 of ? = 40
24 × √? + 4008 ÷ 24 = 40% of 200 + 327
7(1/2) – 3(5/6) = ? − 2(7/12)
280 ÷ 14 + 11 × 12 – 15 × 6 = ?
1550 ÷ 62 + 54.6 x 36 = (? x 10) + (28.5 x 40)
25% of 1000 + 10% of 150 – 22 × ? = 45
√ 729 × 5 – 220 % of 15 + ? = 120% of 160
What will come in the place of question mark (?) in the given expression?
(40% of ? × 43 ) – 232 = 751
180 % of 45 + √144 × 8 = ?2 + 80 % of 70
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