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    Question

    What is the average of the squares of the first 35

    natural numbers?
    A 408 Correct Answer Incorrect Answer
    B 414 Correct Answer Incorrect Answer
    C 426 Correct Answer Incorrect Answer
    D 432 Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Sum of squares of first 'n' natural numbers = n ├Ч (n + 1) ├Ч (2n + 1) ├╖ 6
    So, average = n ├Ч (n + 1) ├Ч (2n + 1) ├╖ 6n = (n + 1) ├Ч (2n + 1) ├╖ 6
    = (35 + 1) ├Ч (2 ├Ч 35 + 1) ├╖ 6
    = 36 ├Ч 71 ├╖ 6
    = 426

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