KL Rahul has an average score of 75 runs in 130 innings.

Solution

ATQ, Let highest score = H Let lowest score = L Total runs in 130 innings: Total = 75 × 130 = 9750 After removing highest and lowest innings: Number of innings left = 130 − 2 = 128 New average = 75 − 2 = 73 So, total runs in remaining 128 innings: New total = 73 × 128 = 9344 Runs removed (highest + lowest): H + L = 9750 − 9344 = 406 Also given: H − L = 170 Solve the two equations: H + L = 406 H − L = 170 Add them: 2H = 406 + 170 = 576 H = 576 ÷ 2 = 288 Hence, the highest runs scored in an innings = 288