Question
In a class of 55 students, the ratio of boys to girls is
5:6. The average weight of a boy exceeds the average weight of a girl by 8 kg. Additionally, the ratio of the total weight of all the boys to that of all the girls is 15:14. Determine the average weight of a boy in the class.Solution
Number of boys in the class = 55 X (5/11) = 25 Number of girls in the class = 55 - 25 = 30 Let the average weight of a girl in the class = 'y' kg Then, average weight of a boy in the class = (y + 8) kg Total weight of all girls in the class = 30 X y = '30y' kg Total weight of all boys in the class = 25 X (y + 8) = (25y + 200) kg According to the question, (25y + 200):(30y) = 15:14 Or, 350y + 2800 = 450y So, y = 2800 ÷ 100 = 28 Therefore, average weight of a boy in the class = 28 + 8 = 36 kg
Simplify the following trigonometric expression:
...
12 cos 68o cosec 22o - 3 cot 72o cot 18o- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
√65 of 14.97 + √50 = (12.02)2 - ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
181.87 ÷ 13.89 X 8.13 + ? = 11.852Â
`[(7.99)^2 - (13.001)^2 + (4.01)^3]^2=` ?
(24.88% of 4879.79) + 20.030 × 13.88 of 13.86 + 46.21 = ? + (13.22)²
(8.86)² × (15.01)² ÷ √624.99 = 9?
What approximate value should come in the place of (?) in the following questions?
42.98% of 849 + 18.45% of 1201 ≈ ?
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