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    Question

    Four numbers are arranged in ascending order. When the

    first two numbers are increased by the number equal to their position, and the last two numbers i.e. the 3rd and 4th number are increased by 6 and 5 respectively, the series thus formed is in A.P. If the first number is 3 less than the 2nd number, and the sum of all the numbers is 28, then find the average of the last three numbers.
    A 12.5 Correct Answer Incorrect Answer
    B 22.2 Correct Answer Incorrect Answer
    C 8.5 Correct Answer Incorrect Answer
    D 19.9 Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    ATQ, Let the numbers be a, b, c, and d. According to the question, (b + 2) тАУ (a + 1) = (c + 6) тАУ (b + 2) Or, 2b = a + c + 3тАжтАж (1) Also, (c + 6) тАУ (b + 2) = (d + 5) тАУ (c + 6) Or, 2c = b + d тАУ 5тАжтАж (2) Let a = x Then, b = x + 3 From (1), c = x + 5 And, from (2), d = x + 11 According to the question, (x + x + 3 + x + 5 + x + 11) = 28 Or, 4x + 19 = 28 Or, 4x = 9 Or, x = 2.25 Therefore, average of the last three numbers = (x + 3 + x + 5 + x + 11)/3 = (2.25 + 3 + 2.25 + 5 + 2.25 + 11)/3 = 25.5/3 = 8.5

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