Question
"In a group of four investors in stocks, the highest
earner makes Rs. 5 lakh per month, while the lowest earner makes Rs. 2.4 lakh per month. Now, we want to determine which of the following statements is/are true: I. The average monthly investment of the investors can be Rs. 3.3 lakh. II. The average monthly investment of the investors can be Rs. 3 lakh. III. The difference between the maximum and minimum possible average monthly investments of the investors is Rs. 1.30 lakhs. You need to identify the statement(s) that hold true."Solution
ATQ, Maximum possible average investment of the investor will be achieved when three people earn the maximum possible investment i.e., Rs. 5 lakh per month. So, maximum possible average monthly investment of the investors = (5 + 5 + 5 + 2.4) ÷ 4 = Rs. 4.35 lakh Minimum possible average investment of the investor will be achieved when three people earn minimum possible investment i.e., Rs. 2.4 lakh per month. So, minimum possible average monthly investment of the investor = (2.4 + 2.4 + 2.4 + 5) ÷ 4 = Rs. 3.05 lakh Statement I: Since, minimum possible average monthly investment of the investor = (2.4 + 2.4 + 2.4 + 5) ÷ 4 = Rs. 3.05 lakh So, statement I is true. Statement II: Since, minimum possible average monthly investment of the investor = (2.4 + 2.4 + 2.4 + 5) ÷ 4 = Rs. 3.05 lakh So, statement II is not true For statement III: Required difference = 4.35 - 3.05 = Rs. 1.30 lakh Statement III: Since, difference between maximum and minimum investment of the investor = 1.35 - 3.05 = Rs. 1.30 lakh So, statement III is true.
- An equilateral triangle has an altitude of 21√3 cm. Calculate the radius of its incircle.
- Find the area of a triangle whose base is 15.4 cm and corresponding altitude is 20.8 cm.
- In triangle DEF, GH is drawn parallel to side EF. If DG = 9 cm, GE = 3 cm and DH = 6 cm, find DF.
- The base of a right pyramid is an equilateral triangle with side 12 cm. If the height of the pyramid is 40√3 cm, calculate the volume of the pyramid.
In the given figure, AB ∥ QP, AB = x, PQ = x + 10, RB = x/2, BP = x + 1. Find PQ.
The area of an isosceles triangle ABC is 8√5 cm². In this triangle, sides AB and BC are equal in length, and the base AC has a length of 8 cm. Determ...
If the side of an equilateral triangle is 12cm, then find the area (in cm 2 ) of the triangle (correct to two decimal places).
The area of two similar triangles is 361 cm² and 324 cm², respectively. What is the ratio of their corresponding altitudes?
In a triangle ABC, the lengths of sides AB, BC, and AC are 13 cm, 14 cm, and 15 cm, respectively. Find the area of the triangle.
What is the height of an equilateral triangle with a side length of 8√3 cm?
Relevant for Exams:
