Question
Ram, Shyam, Rohan, Reeta, and Mukesh are five members of
a family who are weighed consecutively, and their average weight is calculated after each member is weighed. If the average weight increases by 2 kg each time, how much heavier is Mukesh than Ram?Solution
If Average of Ram = x kg   Shyam= x+2 kg      Rohan = x+4 kg Reeta =x+6 Mukesh = The average increased up to Reeta is 6 kg if Average of Ram = x Average up to Reeta = x + 6 Again 2 kg increase with Mukesh so, 2 kg per 5-person increase = 10kg Mukesh 10 kg more than Reeta = x+6+10= x+16 Then heavier is Mukesh than Ram = Mukesh - Ram = x+16-x= 16kg
Statements: Â A % B & G % B; B # L & J; J @ K # S
Conclusions:
I. L @ K
II. A % K
III. S @ B
...Statements: M = R ≥ S , N = O > Q, Q > W = A < S
Conclusions :I. N ≥ S
II. W > R
III. O ≤ S
Statements: A$K; E#N; K@E
Conclusions:
I) A$N
II) A@N
Which of the following letters should be placed in the blank spaces respectively (in the same order from left to right) to complete the given expression...
What is the suitable sign that should be placed so that O > K is true, and J ≤ M is true in the relation 'J = K ≤ L ( ) M < N = O'?
Statements : Z < S < W < D; E ≤ C ≤ Y < D; U < T < S ≤ V
Conclusions :
I. V > Z
II. C < U
III. V > E
Statements: M > T, P > R, T = Q, U ≥ Q, P = U
Conclusion:
I. M ≥ R
II. R > M
Statements: T @ A % S $ L © JÂ
Conclusions:Â
 I. T % LÂ
II. T $ LÂ
III. S # J
Statements: A > C = B ≥ D ≥ F, B = G ≤ H < E
Conclusions:
I. A > G
II. H ≥ F
III. E > C
Statements: R = S > Y ≥ T = W ≥ U > V > X
Conclusions:
I. Y < X
II. S > V
III. U ≤ RRelevant for Exams:
