Question
Ram, Shyam, Rohan, Reeta, and Mukesh are five members of
a family who are weighed consecutively, and their average weight is calculated after each member is weighed. If the average weight increases by 2 kg each time, how much heavier is Mukesh than Ram?Solution
If Average of Ram = x kg Shyam= x+2 kg Rohan = x+4 kg Reeta =x+6 Mukesh = The average increased up to Reeta is 6 kg if Average of Ram = x Average up to Reeta = x + 6 Again 2 kg increase with Mukesh so, 2 kg per 5-person increase = 10kg Mukesh 10 kg more than Reeta = x+6+10= x+16 Then heavier is Mukesh than Ram = Mukesh - Ram = x+16-x= 16kg
More Average Questions
- Determine the final value of this expression:
(1/5) of {5⁴ - 24 × 14 + 12 × 18 - 10.5 of 10²} 3% of 842 ÷ 2% of 421 = ?
√225 + 27 × 10 + ? = 320
- Determine the value of ‘p’ if p = √529 + √1444
45 % of 180 + √144 * 8 = ?2 + 70 % of 80
Determine the value of 'p' in following expression:
720 ÷ 9 + 640 ÷ 16 - p = √121 X 5 + 6²- 7?2 = √20.25 × 10 + √16 + 32
- What will come in place of the question mark (?) in the following questions?
(2⁴ + 6²) ÷ 2 = ? 18(1/3) + 9(2/3) – 10(1/3) = 1(2/3) + ?
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