Question
If average of first 9 numbers is (n – 50) and the sum
of remaining number is 1620. Find the value of ‘n’, if the average of 21 numbers is ‘n’.ÂSolution
According to the question, => 21n = 9 × (n – 50) + 1620 => 21n - 9n = 1620 – 450 => n = 97.5
19.912 - (599.98 - 96.01 ÷ 3.01) ÷ 1.98 = ? + √254
185.92 ÷ 5.98 - (4.002)2 + 114.03 of 5.03 ÷ 18.99 of 6.04 = 5.01 of 2.99 + ? ÷ 12.02
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12.05% of 1399. 93 + 24.95 × 15.05 - 319.04 = ?Â
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