Question
The average mark obtained by 160 candidates in a certain
examination is 60. If the average marks of passed candidates are 65 and that of the failed candidates is 25, then what is the number of candidates who passed in the examination?Solution
According to question, => 65 × x + 25 × (160 − x) = 160 × 60 => 65x + 4000 – 25x = 9600 => x = 140
I). 5p2 Â - p - 4 = 0
II). q2 - 12q + 27 = 0
I. y/16 = 4/yÂ
II. x3 = (2 ÷ 50) × (2500 ÷ 50) × 42 × (192 ÷ 12)
I). p2 + 8p + 15 = 0
II). q2 + 9q + 20 = 0
I. 2x² + 11x + 12 = 0
II. 2y² + 19y + 45 = 0
I:Â x2Â - 33x + 242 = 0
II:Â y2Â - 4y - 77 = 0
I. 6x² - 23x + 7 = 0
II. 6y² - 29y + 9 = 0
I. 6x2 + 23x + 10 = 0
II. 2y2 - 3y - 5 = 0
I. 8/(21x) - 2/7 = 0
II. 16y² - 24y +9 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 4x² - 12x + 9 = 0
Equation 2: 2y² + 8y + 6 = 0
