Question
There are three numbers such that when the average of
any of the two numbers is added with the third number, sum obtained will be 120, 124 and 128. Find the average of all three numbers.Solution
Let the three numbers be a, b and c respectively. According to question; (a + b + 2c) = 120 × 2 = 240……………..(1) (a + 2b + c) = 124 × 2 = 248……………..(2) (2a + b + c) = 128 × 2 = 256……………..(3) From equation (1), (2) and (3) 4 × (a + b + c) = 744 a + b + c = 186 (a + b + c)/3 = 62
19.89% of 449.67 + 14.67% of 299.89 - 9.89% of 99.79 = ?
`(sqrt(960.87)xx9.932+sqrt(629.998)xx26.385)/(sqrt(1028.902)xx4.977)=?`
Find the approximate value of Question mark(?). There is no requirement to find the exact value.
? = 200.14 + 27.98 × 16.05 − (10.03)² - 12.9...
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
1299.999 ÷ 325.018 × 24.996 = ?
What approximate value should replace the question mark?
99.95 − √529 × 3 + 1439.80 ÷ 12.02 = ?
619.97 ÷ 20.01 X 124.99 ÷ 24.91 = ?
124% of 620.99 + 11.65% of 1279.23 = ?
What approximate value should replace the question mark?
9.96% of 1200.10 − 25% of 4800 = ? − 7000.20
