Question
The average daily income of a daily wage worker, in the
month of July is Rs. 120. If his average income on 1st 12 days of the month is Rs. 80 and on last 16 days of the month is Rs. 120, then find his average income on remaining three days of the month.Solution
His total income in the month = 31 × 120 = Rs. 3720 His income of 1st 12 days = 12 × 80 = Rs. 960 His income in last 16 days = 16 × 120 = Rs. 1920 Therefore, his income in the remaining two days = 3720 – (960 + 1920) = Rs. 840 Required average = (840/3) = Rs. 280
The value of 0∫π cos3x dx is –
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