Question
Four persons ‘A’, ‘B’, ‘C’ and ‘D’ have
different amounts with them. ‘D’ has twice amount than that of ‘A’. The amount ‘B’ has is 12.5% more than that of ‘D’. The amount ‘C’ has is equal to the average amount all four persons have. If the sum of the average amount all four have and the amount ‘A’ has is Rs. 2200, then find the amount ‘B’ has.Solution
Let ‘A’ has Rs. a Therefore, amount possessed by ‘D’ = Rs. 2a Amount possessed by ‘B’ = 1.125 × 2a = Rs. 2.25a Let the average amount possessed by all four be Rs. x Therefore, amount possessed by ‘B’ = Rs. x According to the question, 2.25a + 2a + a = 4x – x Or, 5.25a = 3x Or, x/a = 7/4 Therefore, a = 2200 × 4/11 = Rs. 800 Amount possessed by ‘B’ = 2.25a = Rs. 1800
Find the missing number, in the given number series.
6, 12, 36, ?, 720, 4320
In each of the following number series, one term is missing. Find the missing term.
4, 9, 16, 25, 36, ?
What will come in place of the question mark (?) in the following series?
120, 130, ?, 140, 100, 150
250 25 5 ? 0.6 0.3
52, 77, 127, ?, 302, 427
- What will come in place of the question mark (?) in the following series?
712, ?, 576, 508, 440, 372 42, 48, 60, 84, 132, ?
1595, 1083, 740, 524, 399, ?
What will come in place of the question mark (?) in the following series?
80, 83, 88, 95, 106, ?
25, ?, 87, 159, 269, 425
