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Let the fixed charge be Rs. 'F' Let the variable charge per plate be Rs. 'V' ATQ; F + 200V = 400000 ....... (I) F + 300V = 575000 ........ (II) On subtracting equation (I) from equation (II), we have; 100V = 175000 Or, V = 1750 So, F + 200 X (1750) = 400000 Or, F = 400000 - 350000 So, F = 'x' = 50,000 So, fee of 600 plates = 50000 + 1750 X 600 = Rs. 11,00,000 Since, 22x = 22 X 50000 = 1100000
Simplify-
x + 3(y + x – 2) – (x + y).
24 × √? + 4008 ÷ 24 = 40% of 200 + 327
Find the value of the expression:
18 + 12 – 4 × [22 + 6 – 2 × (38 – 23)]
√(82 × 7 × 52 - 175) = ?
180 % of 45 + √144 × 8 = ?2 + 80 % of 70
136% of 560 - 2/7 of 630 + 45% of 420 =?
25% of 240 + √? = (2/3) × 120