Question
14, 28, 56, 112, ...... The sum of first 10 numbers in
the series is:Solution
A Geometric Progression with first term ‘a’ = 14 and common ratio ‘r’ = 2. G.P = Sn = a(rn – 1)/(r – 1) n = 10 Considering the given series 14, 28, 56, 112, ...... Sn = a(rn – 1)/(r – 1) S10 = 14(210 – 1)/(2 – 1) = 14 x 1023 = 14322
60  61  126  387  ?   7845
72 85 103 126 154 ?
...231Â Â Â 451Â Â Â Â Â Â 671Â Â Â Â Â 242Â Â Â Â Â Â 485Â Â Â Â Â Â Â 264
...48Â Â Â 83Â Â Â 118Â Â Â 153Â Â Â 188Â Â Â ?
17 ? 33 44 57 72
...362Â Â Â 284Â Â Â 393Â Â Â Â 451Â Â Â Â 144Â Â Â Â Â 221
...3720 3842 ? 4092 4220 4350
18, 32, 50, 82, 132, ?
35.25 71 146 296 624 1376
...20Â Â Â 60Â Â Â Â 150Â Â Â Â 300Â Â Â 450Â Â Â ?