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      Question

      The 11th term of an AP is 80 less than the

      first term. If the second term is 88, find the third term.
      A 60 Correct Answer Incorrect Answer
      B 90 Correct Answer Incorrect Answer
      C 120 Correct Answer Incorrect Answer
      D 80 Correct Answer Incorrect Answer

      Solution

      Let the first term is ‘a’ and common difference is‘d’. T2 = a + d = 88----(1) According to question T1 – T11 = 80 ⇒ a - (a + 10d) = 80 ⇒ - 10d = 80 d = - 8 From equation (1) a + (- 8) = 88 ⇒ a = 96 Third term T3 = a + 2d ⇒ 96 + 2 × - 8 = 96 – 16 = 80 ∴ Required answer is 80 .

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