Question
The 11th term of an AP is 80 less than the
first term. If the second term is 88, find the third term.Solution
Let the first term is ‘a’ and common difference is‘d’. T2 = a + d = 88----(1) According to question T1 – T11 = 80 ⇒ a - (a + 10d) = 80 ⇒ - 10d = 80 d = - 8 From equation (1) a + (- 8) = 88 ⇒ a = 96 Third term T3 = a + 2d ⇒ 96 + 2 × - 8 = 96 – 16 = 80 ∴ Required answer is 80 .
((67)32 × (67)-18 / ? = (67)βΈ
What will come in the place of question mark (?) in the given expression?
?% of (112 X 3 + 164) + 75 = 2 X 140 + 35
20% of 450 - 15% of 400 = 25% of ?
β121 + β961β β289 =?2
45% of 1020 + ?% of 960 = 747
(γ(0.4)γ^(1/3)Β Γ γ(1/64)γ^(1/4)Β Γ γ16γ^(1/6)Β Γ γ(0.256)γ^(2/3))/(γ(0.16)γ^(2/3)Β Γ 4^(-1/2)Β Γγ1024γ^(-1/4) ) = ?
(512) (2/3) Γ β64 Γ· (512) (1/3) = (64) (?/2) Γ· (2)6Β
1231 + 1312 + 2113 β 3211 = ?
Simplify the following expression:-
Relevant for Exams:
