Question
28 men and 21 women can complete a work in 16 days. All
of them start working together and after working for 12 days the women stopped working. All men alone complete the remaining work in 8 days. How many days will it take for completing the entire work if only 21 women are employed on the job?Solution
28 men and 21 women can complete the work in 16 days.  ∴ Work done by them in 12 days = 12/16 = 3/4  Remaining 1-3/4 = ¼ work is completed by 28 men in 8 days.  => Time taken by only 28 men to complete the whole work = 4 x 8 = 32 days.  Work done by 21 women in a day = 1/16 – 1/32 = 1/32  ∴ Time taken by 21 women to complete the work = 32 days
Simplify the following trigonometric expression:
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12 cos 68o cosec 22o - 3 cot 72o cot 18o- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
√65 of 14.97 + √50 = (12.02)2 - ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
181.87 ÷ 13.89 X 8.13 + ? = 11.852Â
`[(7.99)^2 - (13.001)^2 + (4.01)^3]^2=` ?
(24.88% of 4879.79) + 20.030 × 13.88 of 13.86 + 46.21 = ? + (13.22)²
(8.86)² × (15.01)² ÷ √624.99 = 9?
What approximate value should come in the place of (?) in the following questions?
42.98% of 849 + 18.45% of 1201 ≈ ?
