Question
Find the approximate value of Question mark(?) for given
equation.Β 104.85% of 479.89 β β2400.91 + (71.92 Γ· 6.03) Γ 24.85 = ?Solution
104.85% of 479.89 β β2400.91 + (71.92 Γ· 6.03) Γ 24.85 105% of 480 β β2401 + (72 Γ· 6) Γ 25 105% of 480 = (105/100) Γ 480 = 504 β2401 = 49 72 Γ· 6 = 12 12 Γ 25 = 300 Required value = 504 β 49 + 300 = 755 Correct option: a
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