Question
Find the approximate value of Question mark(?) for given
equation. 104.85% of 479.89 – √2400.91 + (71.92 ÷ 6.03) × 24.85 = ?Solution
104.85% of 479.89 – √2400.91 + (71.92 ÷ 6.03) × 24.85 105% of 480 – √2401 + (72 ÷ 6) × 25 105% of 480 = (105/100) × 480 = 504 √2401 = 49 72 ÷ 6 = 12 12 × 25 = 300 Required value = 504 – 49 + 300 = 755 Correct option: a
More Approximation Questions
Simplify the following trigonometric expression:
...
12 cos 68o cosec 22o - 3 cot 72o cot 18o- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
√65 of 14.97 + √50 = (12.02)2 - ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
181.87 ÷ 13.89 X 8.13 + ? = 11.852
`[(7.99)^2 - (13.001)^2 + (4.01)^3]^2=` ?
(24.88% of 4879.79) + 20.030 × 13.88 of 13.86 + 46.21 = ? + (13.22)²
(8.86)² × (15.01)² ÷ √624.99 = 9?
What approximate value should come in the place of (?) in the following questions?
42.98% of 849 + 18.45% of 1201 ≈ ?
