New Enroll in RBI Grade B New Batch - Starts on May 21

    Question

    Find the approximate value of Question mark(?) for given

    equation.  104.85% of 479.89 – √2400.91 + (71.92 ÷ 6.03) × 24.85 = ?
    A 755 Correct Answer Incorrect Answer
    B 770 Correct Answer Incorrect Answer
    C 795 Correct Answer Incorrect Answer
    D 830 Correct Answer Incorrect Answer
    E None of the above Correct Answer Incorrect Answer

    Solution

    104.85% of 479.89 – √2400.91 + (71.92 ÷ 6.03) × 24.85 105% of 480 – √2401 + (72 ÷ 6) × 25 105% of 480 = (105/100) × 480 = 504 √2401 = 49 72 ÷ 6 = 12 12 × 25 = 300 Required value = 504 – 49 + 300 = 755 Correct option: a

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