Question
If tan θ + cot θ = 16, then find the value of
tan2θ + cot2θ.Solution
We know that, (a + b) 2 = a2 + b2 + 2ab
So, (tan θ + cot θ) 2 = tan2 θ + cot2 θ + 2 x tan θ x cot θ
So, 162 = tan2 θ + cot2 θ + (2 x 1)
So, tan2 θ + cot2 θ = 256 - 2 = 254
More Approximation Questions
12.5% of (100 + ?) = 40
2/9 of 5/8 of 3/25 of ? = 40
24 × √? + 4008 ÷ 24 = 40% of 200 + 327
7(1/2) – 3(5/6) = ? − 2(7/12)
280 ÷ 14 + 11 × 12 – 15 × 6 = ?
1550 ÷ 62 + 54.6 x 36 = (? x 10) + (28.5 x 40)
25% of 1000 + 10% of 150 – 22 × ? = 45
√ 729 × 5 – 220 % of 15 + ? = 120% of 160
What will come in the place of question mark (?) in the given expression?
(40% of ? × 43 ) – 232 = 751
180 % of 45 + √144 × 8 = ?2 + 80 % of 70
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