Question
5 (1/2)% of 3599.67 + {18.11% of 2499.67} + √255.11 -
10% of 1799.99 - (63.01 – 47.08) = ? What approximate value should come in place of (?) in the following questions (Note: You are not expected to calculate the exact value.)Solution
5 (1/2)% of 3599.67 + {18.11% of 2499.67} + √255.11 - 10% of 1799.99 - (63.01 – 47.08) = 5 (1/2)% of 3600 + {18% of 2500} + √256 - 10% of 1800 - (63 – 47) = 5 (½)% = 11/2% = (11/200). = 11/200 × 3600 = 198. 18% of 2500 = (18/100) × 2500 = 450. √256 = 16. 10% of 1800 = (10/100) × 1800 = 180. 63 - 47 = 16. Adding and subtracting: 198 + 450 + 16 - 180 - 16 = 468. Correct answer: d)
4, 6, 12, 30, ?, 315, 1260
Find the missing term in the series:
1, 4, 9, 16, 25, ?, 49
36, 48, 24, 60, ?, 72
?, 15, 45, 225, 1575, 14175
What should come in place of (?) question mark in the given number series.
2, 6, 15, 31, 56, ?
10,14,26,42,70,?
53 × 38 + 32 × ∛54872 = ?
168, 164, 155, 139, ?, 78
18, 30, 46, 66, 90, ?
152 142 122 ? 52 2
Relevant for Exams:
