Question
[15.87% of 599.97 + 40.08 × ?] ÷ 4.04 =
8.082.02 What approximate value will come in place of the question mark (?) in the following question?(Note: You are not expected to calculate the exact value.)Solution
ATQ, [15.87% of 599.97 + 40.08 × ?] ÷ 4.04 = 8.08 2.02 [16% of 600 + 40 × ?] ÷ 4 ~ 82 96 + 40 × ? ~ 256 ? × 40 ~ 160 ? ~ 160 ÷ 40 ? ~ 4
(22.03 + 89.98) ÷ 14.211 = 89.9 – 25.23% of ?
39.9% of 1720 + 80.2% of 630 = 89.9% of 1280 + ?
[√ (121.23) ÷ √ (12100.04)] × √ 80.95 = 3/10 + ? ÷ 4
...40.93√? + √6625 + √6920 + √? = 205.7542`xx` 7.654
13.232 + 19.98% of 549.99 = ? × 8.99
(29.892 × √290) + 32.98 × 6.91 = ?
(`sqrt(224.95)` `xx` `sqrt(440.89)` ) + (`sqrt(783.82)` `xx` `sqrt(440.87)` ) = ? + 150.03% of 120.33 - 139.86% of 1249.88
...8.15 of 124.95 ÷ 40.13 + 249.84 X 14.18 - √325 X 149.87 = ? X 10.85
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
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