Question
The Average of P1, P2, and P3 is 60. Given that P1 is
equal to 1/3rd of this average, what is the average value of P2 and P3?Solution
ATQ, Average = Sum of quantities / No. of quantities Calculations: (P1 + P2 + P3)/3 = 60 ⇒ P1 + P2 + P3 = 180 ⇒ 20 + P2 + P3 = 180 ⇒ P2 + P3 = 160 Now, the average of P2 and P3 is = (P2 + P3) / 2 = 160 / 2 = 80
10.232 + 19.98% of 539.99 = ? × 7.99
(1560.23 ÷ 25.98) + (768.32 ÷ 23.9) + 1814.11 = ?
(56.03 + 112.98) ÷ 13.211 = 89.9 – 25.23% of ?
? = 650.24 + 1124.97 – 14.992 Â
52.08% of 645.92 + 1840% of 47.96 = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
8.992 + (5.01 × 4.98) + ? = 224.03
The average of 5 positive integers was initially computed as 30. However, it was discovered later that an error had occurred duri...
 ?² × 55% of (29 + 32 - 41) = 41.66% of 216 + 9
2280.03 ÷ 59.98 x 59.9 = ? + 30.32
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