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ATQ, Average = Sum of quantities / No. of quantities Calculations: (P1 + P2 + P3)/3 = 60 ⇒ P1 + P2 + P3 = 180 ⇒ 20 + P2 + P3 = 180 ⇒ P2 + P3 = 160 Now, the average of P2 and P3 is = (P2 + P3) / 2 = 160 / 2 = 80
A can do a work in 10 days and B in 15 days. If they work on it together for 4 days then in how many days the remaining work will be completed by B?
A istwice as efficient as B and can finish a piece of work in 22 days less than B. B can finish this work in how many days?