Question
A, B, and C can complete a piece of work separately in
10, 20 and 40 days, respectively. In how many days will the work be completed if A is assisted by both B and C every third day?Solution
AÂ Â Â Â Â Â Â Â Â Â Â Â BÂ Â Â Â Â Â Â Â Â Â Â Â C 10Â Â Â Â Â Â Â Â Â Â 20Â Â Â Â Â Â Â Â Â Â 40 Â Â Â Â Â Â Â Â Â Â Â Â Â Â 40Â Â Â Â Â Â Â Â Â Â Total work 4Â Â Â Â Â Â Â Â Â Â Â Â 2Â Â Â Â Â Â Â Â Â Â Â Â 1Â Â Â Â Â Â Â Â Â Â Â Â Efiici The work of first 3 days =4+4+(4+2+1) =15units Similarly, the Next 3 days work=15units After 6days remaining work =40-(15+15) =10units 7days by A=4unit 8days by A=4units 9 days by A, B, C=2/7 Total days=8+2/7=58/7days.
Chemical equation is balanced according to the law of
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